Shell 006: Replacing String with incrementing index

Lets say we have some text as below.

header
foo
foo
foo
header
bar
bar
bar
header
baz
baz
baz

where we want the "header" be replaced by "model {1,2,3}".
I was pointed out to a couple of solutions over at LinuxQuestions.org

An awk solution.

$ awk 'BEGIN { cntr = 0 } /header/ { cntr++ ; print "model", cntr } !/header/ { print $0 }' infile

where 'infile' contains the data.

A bash solution.

#!/bin/bash

filename=data

index=1

for entry in `grep -n model $filename`
do
        line=`echo $entry | awk -F":" '{print$1}'`

        sed -e "$line s/model/model $index/" -i $filename

        index=$(($index + 1))
done

An even shorter awk solution.

awk '$0 = /header/?"model "++c:$0' file

A one line bash solution

unset count; while read line; do [[ $line =~ header ]] && line="model $((++count))"; echo "$line" >> oufile; done < infile

Great to have the support from the online community.

Shell 005: Redirect Part of a File

Suppose a file contains data starting from a given keyword (the content above the keyword is considered not relevant). If only the content from after the keyword is to be redirected to a new file (in a batch), this can be done using sed.

for i in file-*.log
do
    sed -n '0,/DONE/!p' $i > ${i/file/new}
done

"!" tells it to ignore everything from the start of the file "0" to the first line containing the keyword "/DONE/", then p makes it print the rest, with a shell redirection of the output to a new file.
Regards to David the H. at LinuxQuestions for pointing this out to me.